Monday, January 14, 2013
Saturday, January 12, 2013
Circular Orifice
Circular Orifice
EXPERIMENT :- CIRCULAR ORIFICE (constant head method )
AIM :- To determine the co-efficient of discharge (Cd) by constant head method
APPARATUS :- 01) Orifice Apparatus
02) Measuring Cylinder
03) Stop watch
THEORY :-
co-efficient of discharge though an orifice is given by
Q = Cd. a. √2g . H1/2
Where
Q = Discharge though the orifice
g = Acceleration due to gravity
Cd = Actual Discharge / Theoretical Discharge
Theoretical Discharge QT = a. √2g . H1/2
H = Water head
Writing the same equation in lo from to linearise
Log Q = ½ log10 H + log10 [Cd. a(√2g)]
Y = m X + C
By plotting Log10 QA Vs Log10 H , the value of Cd can be obtained for the intercept
PROCEDURE :-
01) Close the orifice of the middle wall of the apparatus by a plug. So that only the tank with
orifice plate is ready for experiment
02) Close the orifice with a plug and close the drain pipe with a clip.
03) Admit water in to the tank until a considerable head is built up.
04) Now open the orifice and obtain a constant head by adjusting the inflow Valve. (such
that, inflow = outflow).
05) obtain the time to collect some water in the cylinder and note the head, volume of water
collected and the time to collect the water.
06) Repeat the experiment 3 times with a certain head and repeat the process for about 6
different heads.
Orifice meter
DISCUSSION :-
In this experiment we had to use an orifice meter to determine the co-efficient of discharge by means of constant head method and the principle of Bernoulli’s was based for the experiment. In here we can learn the way how to find the co-efficient of discharge. Correctly using flow measurement apparatus hear we had measure the time (T) which is gone for the water level in to (h) value and was connected three times which followed average of these three values that we taken to calculate because, it can be error if we take the one measurement of the time
There can be the air bubbles with the water, so it can be another matter because the density of the water with the air bubbles is less than the density of the water with out air bubbles. There for at the beginning of this experiment the air bubble are allowed to remove
While we were doing this practical we can see some errors but we can get readings almost correct using above methods.
The equation is taken from beryllium equation for this experiment but the beryllium equation is correct only for the lamina flow of fluids. But the water floe through the orifice isn’t fully lamina flow, so that the value of co-efficient of discharge is not equal to actual co-efficient of discharge value. The height of the water level of the tank is increasing the speed of the flowing water is also increasing then the time which we get is reduced the percentage of error is also increasing.
We have to measure time and volume of the water in the same moment. That can be caused big mistake because we have to get the readings according to our naked eye’s
The errors which are mentioned above are done by us, we can minimize those errors then the accuracy of the experiment can be increased when the constant water volume is measured by using transparent utensil, then we can done the experiment almost correctly.
It is very important in the industrial to find Cd value for the fluids.
Ex:- Oil tank , industrial dryers , irrigation system
We have to find Cd value for the oil tank and irrigation system. Because it must know what is the value of the Cd then we can work easily. In above examples there are orifice meter, consist of flat orifice plate with circular hole drilled
So in industrial application, the Cd value is most important thing in dams the water inlet and outlet holes are also based on this theory.
EXPERIMENT :- CIRCULAR ORIFICE (constant head method )
AIM :- To determine the co-efficient of discharge (Cd) by constant head method
APPARATUS :- 01) Orifice Apparatus
02) Measuring Cylinder
03) Stop watch
THEORY :-
co-efficient of discharge though an orifice is given by
Q = Cd. a. √2g . H1/2
Where
Q = Discharge though the orifice
g = Acceleration due to gravity
Cd = Actual Discharge / Theoretical Discharge
Theoretical Discharge QT = a. √2g . H1/2
H = Water head
Writing the same equation in lo from to linearise
Log Q = ½ log10 H + log10 [Cd. a(√2g)]
Y = m X + C
By plotting Log10 QA Vs Log10 H , the value of Cd can be obtained for the intercept
PROCEDURE :-
01) Close the orifice of the middle wall of the apparatus by a plug. So that only the tank with
orifice plate is ready for experiment
02) Close the orifice with a plug and close the drain pipe with a clip.
03) Admit water in to the tank until a considerable head is built up.
04) Now open the orifice and obtain a constant head by adjusting the inflow Valve. (such
that, inflow = outflow).
05) obtain the time to collect some water in the cylinder and note the head, volume of water
collected and the time to collect the water.
06) Repeat the experiment 3 times with a certain head and repeat the process for about 6
different heads.
Orifice meter
DISCUSSION :-
In this experiment we had to use an orifice meter to determine the co-efficient of discharge by means of constant head method and the principle of Bernoulli’s was based for the experiment. In here we can learn the way how to find the co-efficient of discharge. Correctly using flow measurement apparatus hear we had measure the time (T) which is gone for the water level in to (h) value and was connected three times which followed average of these three values that we taken to calculate because, it can be error if we take the one measurement of the time
There can be the air bubbles with the water, so it can be another matter because the density of the water with the air bubbles is less than the density of the water with out air bubbles. There for at the beginning of this experiment the air bubble are allowed to remove
While we were doing this practical we can see some errors but we can get readings almost correct using above methods.
The equation is taken from beryllium equation for this experiment but the beryllium equation is correct only for the lamina flow of fluids. But the water floe through the orifice isn’t fully lamina flow, so that the value of co-efficient of discharge is not equal to actual co-efficient of discharge value. The height of the water level of the tank is increasing the speed of the flowing water is also increasing then the time which we get is reduced the percentage of error is also increasing.
We have to measure time and volume of the water in the same moment. That can be caused big mistake because we have to get the readings according to our naked eye’s
The errors which are mentioned above are done by us, we can minimize those errors then the accuracy of the experiment can be increased when the constant water volume is measured by using transparent utensil, then we can done the experiment almost correctly.
It is very important in the industrial to find Cd value for the fluids.
Ex:- Oil tank , industrial dryers , irrigation system
We have to find Cd value for the oil tank and irrigation system. Because it must know what is the value of the Cd then we can work easily. In above examples there are orifice meter, consist of flat orifice plate with circular hole drilled
So in industrial application, the Cd value is most important thing in dams the water inlet and outlet holes are also based on this theory.
Torsion test
Torsion test
EXPERIMENT :-Torsion test on a steel shaft of circular section using the Torsion test machine
AIM :- To determine the Modulus of rigidity of mild steel
APPARATUS :- 01) Mild steel shaft ( circular cross section )
02) Testing machine
03) Telescope
04) Scale
05) Mirrors
THEORY :-
T/J=Gθ/L
Where,
T = Torque applied
J = Polar moment of inertia
( J = nd4 /32 , d = diameter of the bar )
G = Modulus of rigidity
θ = Angle of rotation over length L
L = Length of the specimen between two gauge points
tan 2θ = (H-h)/l
when θ is small
θ = (H-h)/2l
let l = Horizontal distance from each mirror to the respective scale
hR and h L = Initial reading of the scales ( Right and left )
HR and HL = Readings of the scales after applying the torque
Then
θR = (HR-hR)/2l - (HL-hL)/2l
There for the equation could be written as,
TL = GJ[ (HR-hR)/2l - (HL-hL)/2l]
On arrangement
HR-hR = (2lL/JG) T + HL-hL
This is from ; Y = m X + C
Therefore, G can be calculate from the gradient of the graph
PROCEDURE :-
Firstly the two telescopes were placed at a point 1000mm away from the relevent
mirrors. Each telescope were adjusted so that the relevant scale was reflected in the mirror.
Then the balancing arm was adjusted by moving the poise to the left end.
At that time torque was zero. though the telescope the readings ( hL & hR ) were
taken. Next the toque was increased by 400 pounds each step and 6 sets of readings
( hL & hR ) were taken as above. Finally the diameter of specimen and the length were
measured .
DISCUSSION :-
Torsion test is applicable for testing brittle materials such as mild steel a and the
test has also been used to determine the forge ability of the materials by means of torsion testing
at elevated temperature
The torque is the product of tangential force multiplied by the radial distance from the twisting axis and the tangent, measured in a unit of N.m. 1b. in torsion testing, the relationship between torque and degree of rotation is graphically presented and parameters such as modulus of rigidity, modulus of rapture and shear strength at proportional limit are generally investigated more ever fracture surfaces of specimens tested and torsion can be used to determine the characteristics of materials whether it would fail in a brittle or a ductile manner.
we did this experiment to determine the modulus of rigidity of mild steel. But when we are doing this experiment there are some mistakes can be happened. This apparatus has been used for a long time for this experiment so the rod has been subjected to torque many times. It may have been more twisted so the apparatus has to put more effort to twist the rod.
When we adjusted the telescopes the scales may be change. because the telescopes were placed so closer to each other so we must pay our special attention on adjusting the telescopes. And also we must focus the telescope properly. Otherwise we can't read the scale well.
When apply the load we must be careful otherwise on additional force will occur and it cause to the error readings. In this experiment we had to take the scale readings using telescope. When we doing that, human errors also happened.
If we be more careful during conduct of the experiment we can minimize the mistakes and errors in this experiment and we can get a more accurate result. In many areas of engineering applications, materials are some subjected to torsion in service. For example drive shaft , axial and twisted drill. More ever structural applications such as bridges, springs car bodies, air plane fuselages and boat hulls are randomly subjected to torsion. The material used in this case should not required only adequate strength but also be able to withstand torque in operation. Even through torsion test is not as universal as torsion test and do not have any standardized testing procedure, The significance lies on particular engineering applications and for the study of plastic flow materials.
EXPERIMENT :-Torsion test on a steel shaft of circular section using the Torsion test machine
AIM :- To determine the Modulus of rigidity of mild steel
APPARATUS :- 01) Mild steel shaft ( circular cross section )
02) Testing machine
03) Telescope
04) Scale
05) Mirrors
THEORY :-
T/J=Gθ/L
Where,
T = Torque applied
J = Polar moment of inertia
( J = nd4 /32 , d = diameter of the bar )
G = Modulus of rigidity
θ = Angle of rotation over length L
L = Length of the specimen between two gauge points
tan 2θ = (H-h)/l
when θ is small
θ = (H-h)/2l
let l = Horizontal distance from each mirror to the respective scale
hR and h L = Initial reading of the scales ( Right and left )
HR and HL = Readings of the scales after applying the torque
Then
θR = (HR-hR)/2l - (HL-hL)/2l
There for the equation could be written as,
TL = GJ[ (HR-hR)/2l - (HL-hL)/2l]
On arrangement
HR-hR = (2lL/JG) T + HL-hL
This is from ; Y = m X + C
Therefore, G can be calculate from the gradient of the graph
PROCEDURE :-
Firstly the two telescopes were placed at a point 1000mm away from the relevent
mirrors. Each telescope were adjusted so that the relevant scale was reflected in the mirror.
Then the balancing arm was adjusted by moving the poise to the left end.
At that time torque was zero. though the telescope the readings ( hL & hR ) were
taken. Next the toque was increased by 400 pounds each step and 6 sets of readings
( hL & hR ) were taken as above. Finally the diameter of specimen and the length were
measured .
DISCUSSION :-
Torsion test is applicable for testing brittle materials such as mild steel a and the
test has also been used to determine the forge ability of the materials by means of torsion testing
at elevated temperature
The torque is the product of tangential force multiplied by the radial distance from the twisting axis and the tangent, measured in a unit of N.m. 1b. in torsion testing, the relationship between torque and degree of rotation is graphically presented and parameters such as modulus of rigidity, modulus of rapture and shear strength at proportional limit are generally investigated more ever fracture surfaces of specimens tested and torsion can be used to determine the characteristics of materials whether it would fail in a brittle or a ductile manner.
we did this experiment to determine the modulus of rigidity of mild steel. But when we are doing this experiment there are some mistakes can be happened. This apparatus has been used for a long time for this experiment so the rod has been subjected to torque many times. It may have been more twisted so the apparatus has to put more effort to twist the rod.
When we adjusted the telescopes the scales may be change. because the telescopes were placed so closer to each other so we must pay our special attention on adjusting the telescopes. And also we must focus the telescope properly. Otherwise we can't read the scale well.
When apply the load we must be careful otherwise on additional force will occur and it cause to the error readings. In this experiment we had to take the scale readings using telescope. When we doing that, human errors also happened.
If we be more careful during conduct of the experiment we can minimize the mistakes and errors in this experiment and we can get a more accurate result. In many areas of engineering applications, materials are some subjected to torsion in service. For example drive shaft , axial and twisted drill. More ever structural applications such as bridges, springs car bodies, air plane fuselages and boat hulls are randomly subjected to torsion. The material used in this case should not required only adequate strength but also be able to withstand torque in operation. Even through torsion test is not as universal as torsion test and do not have any standardized testing procedure, The significance lies on particular engineering applications and for the study of plastic flow materials.
THOMSON CALORIMETER
THOMSON CALORIMETER
EXPERIMENT :- Thomson calorimeterOBJECTIVE :- To determine the calorific value of a given solid fuel
APPARATUS :-
·
Coal
·
Potassium Nitrate ( KNO 3 )
·
Potassium Chlorate ( KClO 3 )
·
Nitrate Paper
·
Thompson Calorimeter
·
Furnace tube
·
Thermometer (Digital)
·
Stop Watch
·
Measuring Cylinder
·
Water
2000 ml
THEORY :- ' The heating value' or 'The calorific value ' of a substance usually a fuel is the
amount of energy released during the combustion of a specified amount
of it calorific value is a characteristic of a substance usually the mass such
as (KCal/Kg), (KJ/Kg), (J/mol), etc.calorific value is commonly determined
by using a calorimeter by measuring the increase of the calorimeter's
temperature during the combustion of a substance the amount of heat
generated can be calculated.
Energy released by ( m)g of fuel = Q kJ
Mass of water =
mw
Mass of calorimeter = mc
Specific heat of water = Sw
Specific heat of calorimeter = Sc
Q = (mw * Sw + mc
* Sc) * ∆θ
Calorific value of fuel = (Q / m) * 1000 KJ/Kg
= (mw * Sw + mc *
Sc) * ∆θ * 1000 /m KJ/Kg
Oxygen has to be supplied for the proper combustion of solid fuel inside the calorimeter.
So the required O2 will be obtained by the reaction of chemicals KNO3 and KClO3
Reaction of KNO3 during heating is an " Exothermic reaction " that means it released
heat to the surroundings.
KNO3 (aq) → KNO2 (aq) + O2 (g)
KClO3 (aq) → KClO2 (aq) + O2 (g)
Oxygen has to be supplied for the proper combustion of solid fuel inside the calorimeter.
So the required O2 will be obtained by the reaction of chemicals KNO3 and KClO3
Reaction of KNO3 during heating is an " Exothermic reaction " that means it released
heat to the surroundings.
KNO3 (aq) → KNO2 (aq) + O2 (g)
KClO3 (aq) → KClO2 (aq) + O2 (g)
∆θ = T max - T min
T max = Mean value of the max temperature observed in the experiment
and the extra plated temperature obtained from the graph of
Temperature Vs Time
T min = Initial temperature of the system
PROCEDURE :-
DISCUSSIONand the extra plated temperature obtained from the graph of
Temperature Vs Time
T min = Initial temperature of the system
PROCEDURE :-
- Finely powder the coal provided and mix with KNO3 and KClO3 thoroughly.
- Pack the mixture into the furnace tube along with a piece of Nitrate paper.
- Place 2000 ml of water and the thermometer in the measuring cylinder and note the temperature of the water
- Ignite Nitrate paper-fuse and fix the cover with the stopcock closed and quickly lower into the 2000 ml of water. At the same instance start the stopwatch
- Take the thermometer readings every half a minute until the temperature drops by several degrees.
- When the bubbles stop indicating the stopping of the combustion, open the stopcock and clear the tube using the metal wire provided. Now stir the water by moving the calorimeter up and down whilst temperature readings are taken.
By J.W. THOMAS, F.C.S., F.I.C.
A simple experiment, capable of yielding results which shall be at
least comparative, has long been sought after by large consumers of coal
and artificial fuel abroad in order to ascertain the relative calorific
power possessed by each description, as it is well known that the
proportion of mineral matter and the chemical composition
of coal differ widely. The determination of the ash in coal is not a
highly scientific operation; hence it is not surprising that foreign
merchants should have become alive to the importance of estimating its
quantity. While, however, the nature and quantity of the ash can be
determined without much difficulty, the determination of the chemical
composition of coal entails considerable labor and skill; hence a method
giving the calorific power of any fuel in an exact and reliable manner
by a simple experiment is a great desideratum. This will become more
obvious when one takes into consideration the many qualities and
variable characters of the coals yielded by the South Wales and North of
England
coal fields. Bituminous coals--giving some 65 per cent, of coke--are
preferred for some manufacturing purposes and in some markets.
Bituminous steam coals, yielding 75 per cent, of coke, are highly prized
in others. Semi-bituminous steam coals, yielding 80 to 83 per cent, of
coke, are most highly valued, and find the readiest sale abroad; and
anthracite steam coal (dry coals), giving from 85 to 88 per cent, of
coke (using the term "coke" as equivalent to the non-volatile portion of
the coal) is also exported in considerable quantity. Now the estimation
of the ash of any of these varieties of coal would afford no evidence
as to the class to which that coal belongs, and there is no simple test
that will give the calorific power of a coal, and at the same time
indicate the degree of bituminous or anthracitic character which it
possesses.
In order to obtain such information it is necessary that the
percentage of coke be determined together with the sulphur, ash, and water,
and these form data which at once show the nature of a fuel and give
some indication of its value. To ascertain the quantity of the sulphur,
ash, and water with accuracy involves more skill and aptitude than can
be bestowed by the non-professional public; the consequence is that
experiments entailing less time and precision, like those devised by
Berthier and Thompson, have been tried more or less extensively. In
France and Italy, Berthier's method--slightly modified in some
instances--has been long used. It is as follows:
70 grammes of oxide of lead (litharge) and 10 grammes of oxychloride of lead are employed to afford oxygen
for the combustion of 1 gramme of fuel in a crucible. From the weight
of the button of lead, and taking 8,080 units as the equivalent of carbon,
the total heat-units of the fuel is calculated. This experiment is very
imperfect and erroneous upon scientific grounds, since the hydrogen of
the fuel is scarcely taken into account at all. In the first place,
hydrogen consumes only one quarter as much oxygen as carbon, and,
furthermore, two-ninths only of the heating power of hydrogen is used as
the multiplying number, viz., 8,080, while the value of hydrogen is
34,462. In other words, one-eighteenth only of the available hydrogen
present in the fuel is shown in the result obtained. Apart from this my
experience of the working of Berthier's method has been by no means
satisfactory. There is considerable difficulty in obtaining pure
litharge, and it is almost impossible to procure a crucible which does
not exert a reducing action upon the lead oxide. Some twelve months ago I
went out to Italy to test a large number of cargoes of coal with
Thompson's calorimeter, and since then this apparatus has superseded
Berthier's process, and is likely to come into more general use. Like
Berthier's method, Thompson's apparatus is not without its
disadvantages, and the purpose of this paper is to set these forth, as
well as to suggest a uniform method of working by means of which the
great and irreconcilable differences in the results obtained by some
chemists might be overcome. It has already been observed that a coal
rich in hydrogen shows a low heating power by Berthier's method, and it
will become evident on further reflection that the higher the percentage
of carbon the greater will be the indicated calorific power. In fact a
good sample of anthracite will give higher results than any other class
of coal by Berthier's process. With Thompson's calorimeter the reverse
is the case, as the whole of the heating power of the hydrogen is taken
into account. In short, with careful working, the more bituminous a coal
is the more certain is it that its full heating power shall be exerted
and recorded, so far as the apparatus is capable of indicating it; for
when the result obtained is multiplied by the equivalent of the latent
heat of steam the product is always below the theoretical heat units
calculated from the chemical composition of the coal by the acid of
Favre and Silbermann's figures for carbon and hydrogen. On the other
hand, when the heating power of coal low in hydrogen is determined by
Thompson's calorimeter, much difficulty is experienced in burning the
carbon completely; hence a low result is obtained. From a large number
of experiments I have found that when a coal does not yield more than 86
per cent, of coke, it gives its full comparative heating power, but it
is very questionable if equal results will be worked out if the coke
exceeds the above amount although I have met with coals giving 87 per
cent. of coke which were perfectly manageable, though in other cases the
coal did not burn completely. It will be noted that the non-volatile
residue of anthracite is never as low as 86 per cent., and this,
together with the very dry steam coals and bastard anthracite (found
over a not inextensive tract of the South Wales Coal field), form a
series of coals, alike difficult to burn in Thompson's calorimeter.
Considerable experience has shown that in no single instance was the
true comparative heating power of anthracite or bastard anthracite
indicated. With a view to accelerate the perfect combustion of these
coals, sugar, starch, bitumen, and bituminous coals--substances rich in
hydrogen--were employed, mixed in varying proportions with the
anthracitic coal, but without the anticipated effect. Coke was also
treated in a like manner. Without enlarging further upon these futile
trials--all carefully and repeatedly verified--the results of my
experiments and experience show that for coals of an anthracitic
character, yielding more than 87 per cent. of coke, or for coke itself,
Thompson's calorimeter is not suited as an indicator of their
comparative calorific power, for the simple reason that some of the
carbon is so graphitic in its nature that it will not burn perfectly
when mixed with nitrate and chlorate of potash. A sample of very pure
anthracite used in the experiments referred to, gave 90.4 per cent. of
non-volatile residue, and only 0.84 per cent. of ash. This coal was not
difficult to experiment with, as combustion started with comparative
ease and proceeded quite rapidly enough, but in every instance a portion
of the carbon was unconsumed, and consequently instead of about 13° of
rise in temperature only 10° were recorded
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Torsion test EXPERIMENT :-Torsion test on a steel shaft of circular section using the Torsion test machine AIM :-...
-
THOMSON CALORIMETER EXPERIMENT :- Thomson calorimeter OBJECTIVE :- To determine the calorific value of a given solid fuel APPARAT...